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Xml read

joed's picture

Submitted by joed on April 9, 2009 - 04:47

Hi there, I am having a slight problem with an xml local read. I am currently not receiving any output for an e4x query on the file. Any related info would be great. ************Code************ this.serviceName = "readfile2"; this.documentation = "TODO: Add service level documentation here" ; toString.documentation = "TODO: Add operation level documentation here" ; toString.inputTypes = { /* TODO: Add input types of this operation */ }; toString.outputType = "String"; /* TODO: Add output type here */ //toString.outputType = "#raw"; //toString.outputType = "any"; //toString.outputType = "xml"; function toString() { var file = new File("sample.xml"); file.openForReading(); var readfile = new XML(file.readAll()); file.close(); var keywordread = readfile.Library.Book.Title.toString(); return keywordread } ************Code************ ************XML************-sample.xml GeographySmith ************XML************ Thanks Joe

keith's picture

Have a look at the version sample

Submitted by keith on April 9, 2009 - 08:44.

Hi Joe, You could have a look at the version sample. That's implemented in this same way. Thanks, Keith. Blog : http://www.keith-chapman.org

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joed's picture

I tried the basis of some

Submitted by joed on April 9, 2009 - 09:31.

I tried the basis of some functions of the version script file as the skeleton but have had no luck receiving a string response or error.

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keith's picture

I presume that the problems

Submitted by keith on April 9, 2009 - 09:45.

I presume that the problems you are having is with E4X. For starters just return the complete XML, if that works you can build on that. You could refer [1] for a E4X quick start guide. Thanks, Keith. Blog : http://www.keith-chapman.org [1] http://wso2.org/project/mashup/1.5.1/docs/e4xquickstart.html

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jonathan.wso2.com's picture

Lost your sample XML

Submitted by jonathan.wso2.com on April 13, 2009 - 11:20.

The sample XML didn't come through on your post - I suspect if you remove ".Library" from your query (assuming that's the name of the document element of the XML file) it will work. The new XML() command returns the document element, as opposed to the document node if you're used to DOM or XPath.

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joed's picture

Worked great. Thanks joed

Submitted by joed on April 15, 2009 - 10:12.

Worked great. Thanks joed

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